- #1

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D=distance to star

theta=angle

using the rule D=(d/2)/tan(theta/2)

when d = 300*10tothe6

and theta = 5*10tothe-5

what is the distance to the star in km and light years?

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- #1

- 10

- 0

D=distance to star

theta=angle

using the rule D=(d/2)/tan(theta/2)

when d = 300*10tothe6

and theta = 5*10tothe-5

what is the distance to the star in km and light years?

- #2

Doc Al

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What's the problem?

(d is in what units?)

(d is in what units?)

- #3

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This is as close as i can get:

for this answer i get a result of:

343774677078406.6587981892079753

So, is this answer the number of km?

what is this answer in exponential form? ie: 34 * 10tothepower13?

1 light year is 9.467*10tothepower12, so in light years i think the distance will be:

27 light years

Please let me know if i am right

- #4

Doc Al

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