- #1

- 10

- 0

D=distance to star

theta=angle

using the rule D=(d/2)/tan(theta/2)

when d = 300*10tothe6

and theta = 5*10tothe-5

what is the distance to the star in km and light years?

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter radius
- Start date

- #1

- 10

- 0

D=distance to star

theta=angle

using the rule D=(d/2)/tan(theta/2)

when d = 300*10tothe6

and theta = 5*10tothe-5

what is the distance to the star in km and light years?

- #2

Doc Al

Mentor

- 45,185

- 1,514

What's the problem?

(d is in what units?)

(d is in what units?)

- #3

- 10

- 0

This is as close as i can get:

for this answer i get a result of:

343774677078406.6587981892079753

So, is this answer the number of km?

what is this answer in exponential form? ie: 34 * 10tothepower13?

1 light year is 9.467*10tothepower12, so in light years i think the distance will be:

27 light years

Please let me know if i am right

- #4

Doc Al

Mentor

- 45,185

- 1,514

Share: