Parallel axis theorem for area

In summary, the y-bar, or the average value of y' across all little areas of a shape, is equal to 0 because the y' axis, not the y axis, is defined as the vertical line passing through the centroid. This is due to the fact that the shape can be thought of as made up of many little areas with their own (x', y') coordinates relative to the centroid, and the average value of y' is calculated as 0 by definition of the centroid. Additionally, the second integral is equal to 0 because when calculating y' squared, all products are positive, while in the first integral, some products are negative, resulting in a non-zero value.
  • #1
goldfish9776
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Homework Statement


why the y bar is 0 ? according to the diagram , y ' has certain value , it's not 0 ! can someone help to explain ?

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The Attempt at a Solution

 

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  • #2
[itex]\overline{y}= 0[/itex] because the y' axis, not the y axis, is defined as the vertical line passing through the center of mass.
 
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  • #3
HallsofIvy said:
[itex]\overline{y}= 0[/itex] because the y' axis, not the y axis, is defined as the vertical line passing through the center of mass.
it pass thru centroid , why it is 0 ?
 
  • #4
goldfish9776 said:
it pass thru centroid , why it is 0 ?
The shape can be thought of as made up of many little areas like A. Each little area has its own (x', y') coordinates relative to the centroid. y-bar is here defined as the average value of y' across all these little areas. By definition of centroid, that average is zero.
 
  • #5
haruspex said:
The shape can be thought of as made up of many little areas like A. Each little area has its own (x', y') coordinates relative to the centroid. y-bar is here defined as the average value of y' across all these little areas. By definition of centroid, that average is zero.
why only the second integral = 0 , why not the first integral equal to 0 also ?
 
  • #6
goldfish9776 said:
why only the second integral = 0 , why not the first integral equal to 0 also ?
Because in the first integral, y' is squared.

When y' is by itself, you are adding products of y' dA on either side of the centroidal axis, so some products are negative and some are positive. When you calculate y'2 dA, all of the products are positive, so their sum adds up to a positive, non-zero result.
 
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1. What is the parallel axis theorem for area?

The parallel axis theorem for area states that the moment of inertia of a planar shape about an axis parallel to its centroidal axis is equal to the moment of inertia about the centroidal axis plus the product of the shape's area and the square of the distance between the two axes.

2. Why is the parallel axis theorem important in physics and engineering?

The parallel axis theorem is important because it allows us to calculate the moment of inertia for complex shapes that cannot be easily calculated using basic formulas. This is useful in physics and engineering when analyzing the rotational motion and stability of objects.

3. How is the parallel axis theorem derived?

The parallel axis theorem is derived from the more general parallel axis theorem for moments of inertia, which relates the moment of inertia of a body about any axis to its moment of inertia about a parallel axis through the body's center of mass. This theorem is derived using the basic principles of calculus and geometry.

4. Are there any limitations to the parallel axis theorem for area?

Yes, the parallel axis theorem for area is limited to planar shapes and cannot be applied to objects with complex 3-dimensional shapes. Additionally, it assumes that the shape is made of a uniform material with a constant density.

5. Can the parallel axis theorem be used for non-uniform shapes?

No, the parallel axis theorem can only be used for uniform shapes. For non-uniform shapes, the moment of inertia must be calculated using integration methods or through experimental measurements.

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