A uniform rod of mass M=5.0 kg and length ℓ=20 cm is pivoted on a frictionless hinge at the end of it. The rod is held horizontally and then released. a) Use the parallel-axis theorem to determine the moment of inertia of the rod about the hinge (ie its end). b) Determine the angular velocity of the rod when it reaches the vertical position and the speed of the rod tip’s at this point. I=MR^2 Ok so what I did first was 1/12 ML^2 as "I" about the hinge is 1/12ML2 + (M*(L/2)2) to work out A. I don't really know how to work out b though, apart from possibly using that to work out the distance from the radius and then doing work done to then find out ω, I assume.