 1,166
 5
Diagram shown in attachment. Two inductors having selfinductance L1 and L2 are connected in parallel. The mutual inductance beween the two inductors is M. Determine the equivalent selfinductance Leqv for the system.
I'm pretty much stuck on this one. Since the current splits off and heads in the same direction for each inductor, the contributing emfs are in the same direction for each one but repel each others effects, so I dont think it would be a sum of the inductances. I'm not exactly sure how to take the mutual inductance into account. The answer is:
(L1*L2  M^2)/(L1 + L2  2M)...any ideas?
I'm pretty much stuck on this one. Since the current splits off and heads in the same direction for each inductor, the contributing emfs are in the same direction for each one but repel each others effects, so I dont think it would be a sum of the inductances. I'm not exactly sure how to take the mutual inductance into account. The answer is:
(L1*L2  M^2)/(L1 + L2  2M)...any ideas?
Attachments

4.1 KB Views: 333