Parallel-plate air capacitor

In summary, the given conversation discusses the calculation of capacitance for a parallel-plate air capacitor with specific measurements and an applied electric field. The formula for capacitance is mentioned and advice is given to use this formula to solve the problem.
  • #1
vegamontalvo
2
0
Each plate of a parallel-plate air capacitor has an area of 0.0070 m2, and the separation of the plates
is 0.030 mm. An electric field of 4.0 × 106 V/m is present between the plates. The capacitance of the
capacitor, in pF, is closest to:?


The capacitive network shown is assembled with initially uncharged capacitors. A potential difference, Vab = +100 V, is
applied across the network. The switch S in the network is kept open throughout.
 

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  • #2
Capacitance is electric energy per charge, you should be able to calculate the electric energy for a given charge setup so just put Q -Q on the capacitor and continue on from there.

As for the second it is just about knowing how to calculate parallel and series of capacitors. You should be able to prove these from the definition of capacitance.

If you have any problems try to start, post how far you got and I can give you more from there.
 
  • #3
yes i need help to start! thank you
 
  • #4
welcome to pf!

hi vegamontalvo! welcome to pf! :smile:

(try using the X2 icon just above the Reply box :wink:)
vegamontalvo said:
Each plate of a parallel-plate air capacitor has an area of 0.0070 m2, and the separation of the plates
is 0.030 mm. An electric field of 4.0 × 106 V/m is present between the plates. The capacitance of the
capacitor, in pF, is closest to:?

what formulas do you know relating E d A Q and C for a capacitor ? :smile:
Klockan3 said:
Capacitance is electric energy per charge …

no, capacitance = charge per voltage
 
  • #5


I would like to clarify that the capacitance of the parallel-plate air capacitor can be calculated using the formula C = ε₀A/d, where ε₀ is the permittivity of free space, A is the area of the plates, and d is the distance between the plates. Using the given values, the capacitance of the capacitor is approximately 7.78 pF.

Regarding the second part of the content, I would like to point out that the potential difference, Vab = +100 V, applied across the network will not affect the capacitance of the parallel-plate air capacitor. The capacitance is a physical property of the capacitor and is not affected by external factors such as potential difference.

Furthermore, the switch S being kept open throughout means that no current is flowing through the circuit, and therefore, the capacitor remains uncharged. The potential difference across the network will only be present when the switch is closed and current flows through the circuit.

In conclusion, the capacitance of the parallel-plate air capacitor is approximately 7.78 pF and the potential difference of +100 V across the network will not affect its capacitance as long as the switch remains open.
 

1. What is a parallel-plate air capacitor?

A parallel-plate air capacitor is a device used to store electrical energy. It consists of two parallel conductive plates separated by a small distance and surrounded by air. The plates are connected to a voltage source, creating an electric field between them. This electric field stores energy in the form of electric charge on the plates.

2. How does a parallel-plate air capacitor work?

A parallel-plate air capacitor works by utilizing the concept of capacitance, which is the ability of a system to store electrical energy. The two parallel plates act as conductors, while the air between them acts as a dielectric. When a voltage is applied to the plates, it creates an electric field, which causes a buildup of electric charge on the plates. The amount of charge that can be stored is determined by the distance between the plates and the voltage applied.

3. What are the applications of parallel-plate air capacitors?

Parallel-plate air capacitors have a variety of applications in electronics and technology. They are commonly used in filter circuits to block certain frequencies of electric current. They are also used in radio and television broadcasting to tune frequencies. Additionally, parallel-plate air capacitors are used in energy storage systems, such as in camera flashes and defibrillators.

4. How is the capacitance of a parallel-plate air capacitor calculated?

The capacitance of a parallel-plate air capacitor can be calculated using the formula C = ε₀A/d, where C is the capacitance, ε₀ is the permittivity of free space, A is the area of the plates, and d is the distance between the plates. This formula assumes that the electric field is uniform between the plates and that the plates are large enough to be considered infinite in size.

5. How does the distance between the plates affect the capacitance of a parallel-plate air capacitor?

The distance between the plates of a parallel-plate air capacitor has a direct effect on its capacitance. As the distance between the plates increases, the capacitance decreases, and vice versa. This is because the electric field strength between the plates decreases as the distance increases, resulting in a lower amount of charge being stored on the plates. Therefore, the closer the plates are together, the higher the capacitance will be.

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