(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A small object with a mass of 350mg carries a charge of 30nC and is suspended by a thread between the vertical plates of a parallel-plate capacitor. The plates are separacted by 4 cm. If the thread makes an angle of 15 degrees with the vertical, what is the potential difference between the plates?

3. The attempt at a solution

First, I drew a diagram. Since the object has a + charge, it would be more closer to the negative plate.

[tex]\Delta V=\frac{U_{E}}{q}[/tex]

[tex]U_{E}=qEd[/tex] , [tex]E=\frac{kq}{r^2}[/tex]

Now that I have all the required info to solve for the electrical potential energy, I solved it and put it into the equation: [tex]\Delta V=\frac{U_{E}}{q}[/tex]

For the electrical potential energy I got: 2.023*10^-4J

For the answer (the potential difference) I got: 6742.5V

Does my method seem correct? This is an even problem so I have no way of checking my answer for accuracy. Thanks in adv.

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Parallel-Plate Capacitor

**Physics Forums | Science Articles, Homework Help, Discussion**