Parallel-plate capacitor charge problem

In summary, two 10.0-diameter electrodes, 0.56 apart, form a parallel-plate capacitor attached to a 14 battery. After disconnecting from the battery, the capacitor is not discharged. The charge on each electrode is 1.74*10^-10 coulombs. The capacitor plates have a 10 cm diameter and are 0.56 cm apart. The equation used is C=K*A/d.
  • #1
Allyson
2
0

Homework Statement


Two 10.0 -diameter electrodes 0.56 apart form a parallel-plate capacitor. The electrodes are attached by metal wires to the terminals of a 14 battery. After a long time, the capacitor is disconnected from the battery but is not discharged.
a. What is the charge on each right after the battery is disconnect? What is q1, q2 in coulombs


Homework Equations


C=K*A/d


The Attempt at a Solution

I have tried several attempts, but still have the answer 1.74*10^-10. What have I done wrong.
 
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  • #2
This is how I did the work.
pi*.01/4=.007853982*8.85418/.0056=12.42*10^-12*14=1.74*10^-10, 1.7*10^-10 Answer in 2 significant digit?
 
  • #3
Is one saying that 1.7*10^-10 is the answer?

1.74*10^-10 in two significant digits would be 1.7*10^-10.


It would also help if one provides units. I would guess the capacitor plates have a 10 cm dia, and are 0.56 cm apart?

Also, please write all the equations. Please see - http://hyperphysics.phy-astr.gsu.edu/hbase/electric/capac.html
 

1. What is a parallel-plate capacitor?

A parallel-plate capacitor is a device used to store electrical energy. It consists of two conducting plates separated by a small distance and insulated from each other.

2. How does a parallel-plate capacitor charge work?

When a voltage is applied to a parallel-plate capacitor, one plate becomes positively charged while the other becomes negatively charged. This creates an electric field between the plates, which stores energy in the form of electrical potential energy.

3. What is the equation for calculating the charge on a parallel-plate capacitor?

The equation for calculating the charge on a parallel-plate capacitor is Q = CV, where Q is the charge, C is the capacitance of the capacitor, and V is the voltage applied across the plates.

4. How does the distance between the plates affect the charge on a parallel-plate capacitor?

The distance between the plates of a parallel-plate capacitor is directly proportional to the charge stored on the capacitor. This means that the farther apart the plates are, the higher the charge on the capacitor will be.

5. What is the unit of measurement for capacitance?

The unit of measurement for capacitance is the farad (F). This unit is named after the physicist Michael Faraday and is equivalent to one coulomb of charge per one volt of potential difference.

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