1. The problem statement, all variables and given/known data A proton, accelerated from rest through a potential difference of 1.2 x 10^4 V, is directed at a fixed 5.0 x 10^-6 charge. a) What is the speed of the proton as it leaves the parallel plates? b) What is the distance d from the fixed charge when the proton is stopped? 2. Relevant equations 3. The attempt at a solution A) For part "a" what I did was I used the principle of conservation of energy equation (-Δ Ep = Δ Ek or ΔEp = -ΔEk) and isolated for final velocity. Note: ΔEp = ΔV x q in this question not mgh Δ Ep = -ΔEk Δ V x q = Eki - Ekf Δ V x q = -1/2mvf^2 vf = √(-2ΔV x q/m) then I plugged in all my values and the answer that I got was 1.5 x 10^6 m/s could someone please check this to see if it is correct because this is the first time that I have done these questions and I just want to see if I am doing it right before I proceed to the other questions. B) For part "b" I do not understand the question, could someone please tell me what equations I should be using or point me in the right direction?