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Parallel Resonance Circuit

  1. Oct 27, 2006 #1
    Hi all.

    I have a Parallel Resonant circuit with a Capacitor in Parallel with an Inductor & Resistor in Series together. Capacitor on the left branch and Inductor & Resistor on the right branch.

    The question I would like to ask is what effect does the resistor have on the circuit?

    I believe it may have something to do with the leakage current??? Not really sure though.

    Anyone help out??
  2. jcsd
  3. Oct 27, 2006 #2


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    Gold Member

    It determines the "Q" (Quality Factor) of the resonance. If omega_0 is the resonance angular frequency,

    Q = omega_0 * L / R.

    The width of the resonance at the -3dB (half power) points is

    delta_omega = omega_0 / Q
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