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Parallelogram proof

  • Thread starter jtf2eh
  • Start date
1
0
Parallelogram proof :(

1. Homework Statement
In parallelogram ABCD, P is any point on BC. Prove that triangle APD = triangle ABP + triangle DCP

2. Homework Equations
n/a

3. The Attempt at a Solution
I really don't know where to start :(

any help would be greatly appreciated :)
 

Answers and Replies

HallsofIvy
Science Advisor
Homework Helper
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First do you mean that the areas satisfy that equation? If so just note that the lengths of the bases of the two triangles ABP and DCP add to the length of the base of triangle APD and all three triangles have the same height.
 

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