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Parametric Curve

  1. Feb 24, 2004 #1
    Another question...

    If I were given these equations:

    x = e^t
    y = e^-t

    Then I have to find the cartesian product for this parametric curve and then I have to sketch the graph of the curve. So here's the cartesian product I came up with:

    Solve for t in y, so:

    y = e^-t
    ln y = ln e^-t
    ln y = -t
    t = - ln y

    Then plug in to the x part:

    x = e^-ln y

    Is that part correct?

    I have no idea how to graph this...

    Help appreciated.
  2. jcsd
  3. Feb 24, 2004 #2


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    Gold Member

    Do you know any identities applicable to it?
  4. Feb 24, 2004 #3

    matt grime

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    Simple method: u^{-r}= 1/u^r
    slightly longer metheod, try multiplying x and y together!


    -log(p) = log(1/p)

    any of those help?
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