- #1

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Using the identity [itex] \sin^{2}\theta + cos^{2}\theta = 1 [/itex] would it be [itex] x^{2} + y^{2} = 1 [/itex]?

Thanks

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- Thread starter courtrigrad
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- #1

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Using the identity [itex] \sin^{2}\theta + cos^{2}\theta = 1 [/itex] would it be [itex] x^{2} + y^{2} = 1 [/itex]?

Thanks

- #2

EnumaElish

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Are you sure x and y are independent of t?? If so, the cartsian equation is just the point (0,1)

- #4

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come on its a typo.... [itex] x = \sin(2\pi t ), y = \cos(2\pi t ) [/itex]

thanks

thanks

- #5

HallsofIvy

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Yes, you are correct, since [itex]sin^2(2\pi t)+ cos^2(2\pi t)[/itex].

You should also note that, as t goes from 0 to 1, [itex]2\pi t[/itex] goes from 0 to [itex]2\pi[/itex] so this would be exactly once around the circle.

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