The ellipse [tex]\frac{x^2}{3^2} + \frac{y^2}{4^2} = 1[/tex](adsbygoogle = window.adsbygoogle || []).push({});

can be drawn with parametric equations. Assume the curve is traced clockwise as the parameter increases.

If [tex] x=3cos(t)[/tex]

then y = ___________________________

wouldnt i just sub x into the ellipse equation and solve for y?

well i did that and got [tex]\sqrt{(-1/16*((3*cos(t))^2/9)+1)}[/tex]

but there's a negative sign inside the sqrt function, so it's not possible

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# Homework Help: Parametric Equations of an ellipse

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