Parametric equations

  • Thread starter cmut
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I have tirelessly tried to solve this out seems i need smnes help: if x=2+7cosθ and y=8+3sinθ show that d2y/dx2=(-3cosec3θ)/49
 

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  • #2
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I have tirelessly tried to solve this
You could post what you tried so far.

You can derive an expression y=f(x). Alternatively, there is a nice way to get an expression f(x,y)=0, which can be derived afterwards.
 
  • #3
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I used the formula for d2y/dx2=(d/dθ dy/dx)/dx/dθ, i further used the quotient rule to simplify the expression and found they are not the same i got 21cosec2θ/49.....it seems right but would you think otherwise? i greatly appreciate your feedback Mfb:smile:
 
  • #4
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Okay, I checked it myself, and I get the same result as you.
 
  • #5
HallsofIvy
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I have tirelessly tried to solve this out seems i need smnes help: if x=2+7cosθ and y=8+3sinθ show that d2y/dx2=(-3cosec3θ)/49
dx/dθ= -7 sin(θ) and dy/dθ= 3 cos(θ) so dy/dx= (-3/7) cot(θ)

Then d^2y/dx= d/dx(-(3/7) cot(θ))= (3/7) csc^2(θ) dθ/dx= (3/7) csc^2(θ)/(-7 sin(θ))= -(3/49)csc^3(θ)
 

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