- #1
ILoveBaseball
- 30
- 0
find [tex]\frac{d^2y}{dx^2}[/tex] as a function of [tex]t[/tex], for the given the parametric equations:
x = 2-4*cos(t)
y= 4+cos(t)^2
[tex]\frac{d^2y}{dx^2}[/tex] = _______
dy/dt = [tex]-2*cos(t)*sin(t)[/tex]
second derv. [tex]2*sin(t)^2-2*cos(t)^2[/tex]
dx/dt = [tex]4*sin(t)[/tex]
second derv. [tex]4*cos(t)[/tex]
[tex]\frac{d^2y}{dx^2}[/tex] = [tex]\frac{2*sin(t)^2-2*cos(t)^2}{4*cos(t)}[/tex]
what did i do wrong?
x = 2-4*cos(t)
y= 4+cos(t)^2
[tex]\frac{d^2y}{dx^2}[/tex] = _______
dy/dt = [tex]-2*cos(t)*sin(t)[/tex]
second derv. [tex]2*sin(t)^2-2*cos(t)^2[/tex]
dx/dt = [tex]4*sin(t)[/tex]
second derv. [tex]4*cos(t)[/tex]
[tex]\frac{d^2y}{dx^2}[/tex] = [tex]\frac{2*sin(t)^2-2*cos(t)^2}{4*cos(t)}[/tex]
what did i do wrong?