Parametric line

  • Thread starter lorik
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  • #1
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Homework Statement


The problem is pretty simple but I seem to be missing something essential .Write parametric equation of line which passes through point P0(1,-1,-3) and is parallel with line (x+1)/1=(y+2)/4=(z-1)/0


Homework Equations


solutions are x=2t+1 ,y=4t-1,z=-3


The Attempt at a Solution


I would really really appreciate if u could simply say the magic word because this looks really easy but yet troubling to my brain I think Im tired !
 

Answers and Replies

  • #2
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Homework Statement


The problem is pretty simple but I seem to be missing something essential .Write parametric equation of line which passes through point P0(1,-1,-3) and is parallel with line (x+1)/1=(y+2)/4=(z-1)/0


Homework Equations


solutions are x=2t+1 ,y=4t-1,z=-3


The Attempt at a Solution


I would really really appreciate if u could simply say the magic word because this looks really easy but yet troubling to my brain I think Im tired !
If you know a point on a line and a vector parallel to the line, can you get the parametric equations for the line?

You can extract the coordinates of a vector from the symmetric equations (x+1)/1=(y+2)/4=(z-1)/0; namely <1, 4, 0>.

That should get you started.
 
  • #3
rock.freak667
Homework Helper
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is parallel with line (x+1)/1=(y+2)/4=(z-1)/0
What is the direction of this line?
 
  • #4
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If you know a point on a line and a vector parallel to the line, can you get the parametric equations for the line?

You can extract the coordinates of a vector from the symmetric equations (x+1)/1=(y+2)/4=(z-1)/0; namely <1, 4, 0>.

That should get you started.
And you're Awesome !!
 
  • #5
HallsofIvy
Science Advisor
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In general, any line parallel to
[tex]\frac{x- x_0}{A}= \frac{y- y_0}{B}= \frac{z- z_0}{C}[/tex]

and passing through the point [itex](x_0, y_0, z_0)[/itex] is of the form
[tex]\frac{x-x_1}{A}= \frac{y- y_1}{B}= \frac{z- z_1}{C}[/tex]

That is, it is precisely the numbers A, B, C that determine the direction.
 

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