We're working on the parity operator in my second semester quantum mechanics class and there is one point I am confused about, either in the definition of degeneracy or in the parity operator itself. We talked about a theorem whereby the parity operator and the Hamiltonian cannot share simultaneous eigenkets (or, alternatively, wave functions) if there is a degeneracy in the Hamiltonian, regardless of whether or not parity and the Hamiltonian commute.(adsbygoogle = window.adsbygoogle || []).push({});

However, I thought that the Hydrogen wave functions have a definite parity (going as whether [tex]\ell[/tex] is even or odd), even though the Hydrogen spectrum is highly degenerate ignoring corrections. What am I missing?

Thanks!

Tom

**Physics Forums - The Fusion of Science and Community**

# Parity Operator

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

Have something to add?

- Similar discussions for: Parity Operator

Loading...

**Physics Forums - The Fusion of Science and Community**