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Parrallel Resistance

  1. Feb 8, 2004 #1
    A 6 volt battery supplies a total of 48W to two identicle headlights in parrallel. The resistance in each bulb is:

    My confusion here is that I am not sure where the watts would fit into resistances.

    Could someone lead me in the right directions.

    thanks
    nautica
     
  2. jcsd
  3. Feb 8, 2004 #2

    jamesrc

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    Use the power to find the current through each lightbulb (P = VI); then use Ohm's law to find resistance.
     
  4. Feb 8, 2004 #3
    So

    48W=6VI, so 8 total, which would give 4 in each, right?

    thanks
    nautica
     
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