- #1

jennypear

- 16

- 0

A. How much work is done in each cycle?

work=power(delta t) = 150 W * 1s = 150 J

work =15.0 J per cycle

**got part A correct

B. How much heat is given off in each cycle?

delta internal energy = delta work + delta heat

delta intergy = 0 bc its a complete cycle

delta heat = - delta work

delta heat = 15 J

**Part B isn't coming out...please guide in the correct direction if possible.