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Partial defferentiation

  1. Sep 11, 2008 #1
    I'm not quite sure how this partial d/dx should look

    (x + y) / sqr root(x^2 + y^2)

    Is it (-2)(1/2x)(x+y)/((x^2 +y^2)^3/2) ??

    Please help!
     
  2. jcsd
  3. Sep 11, 2008 #2

    Defennder

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    Homework Helper

    Partial differentiation with respect to x is the same as doing differentiation with respect to x (ie. d/dx), only that every other variable such as y,z are considered constants. So, just replace y with a constant c and evaluate d/dx. When you're done, replace the c's with y and that's the answer.

    Your answer doesn't appear to be correct.
     
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