1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Partial defferentiation

  1. Sep 11, 2008 #1
    I'm not quite sure how this partial d/dx should look

    (x + y) / sqr root(x^2 + y^2)

    Is it (-2)(1/2x)(x+y)/((x^2 +y^2)^3/2) ??

    Please help!
     
  2. jcsd
  3. Sep 11, 2008 #2

    Defennder

    User Avatar
    Homework Helper

    Partial differentiation with respect to x is the same as doing differentiation with respect to x (ie. d/dx), only that every other variable such as y,z are considered constants. So, just replace y with a constant c and evaluate d/dx. When you're done, replace the c's with y and that's the answer.

    Your answer doesn't appear to be correct.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Partial defferentiation
  1. Partial Derivatives (Replies: 2)

  2. Partial derivatives (Replies: 25)

  3. Partial derivative (Replies: 6)

  4. Partial Derivatives (Replies: 8)

Loading...