Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Partial derivative q

  1. Feb 2, 2006 #1
    In determining if a function is exact, here is the question. If V=V(T,P) and PV+RT, show that dV = R/PdT - RT/P2 dP. Is dV an exact differential?
    Do I go about by taking the derivative of R/PdT with respect to T, etc? I know this is not a difficult function, but I just want to make sure I'm approaching it correctly.

    Thanks!
     
  2. jcsd
  3. Feb 2, 2006 #2

    HallsofIvy

    User Avatar
    Science Advisor

    There are several things aobut your post that I do not understand.

    I know what it means for a differential to be exact, but don't know what it means for a function to be exact. Are you talking about a differential?

    Also you say "if V= V(T,P) and PV+RT". Okay, V= V(T,P) is a complete statement- it says that V is function of T and P. But "PV+ RT" is not a complete statement. What about PV+ RT? Is something missing? Was it supposed to be PV+ RT= something?

    Finally, you talk about "taking the derivative of R/PdT with respect to T" but that already is a differential, Don't you mean to diffentiate an equation involving V?

    If PV+ RT= some function, then P dV+ VdP+ dRT+ RdT= the derivative of that function. In particular, if PV+ RT= constant, and R is held constant, then PdV+ VdP+ RdT= 0 so that PdV= RdT- VdP and then
    dV= RdT/P- (V/P)dP. Now that would be what you give IF V/P= RT/P2 (I assume that your P2 was intended to be P2) or
    V= RT/P.

    Now, although you didn't say anything about it, I remember that for an "ideal gas", PV= nRT where R is a constant. If THAT is what you are talking about, then, yes, dV = (R/P)dT - (RT/P2)dP.
     
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook