Partial Derivative of U: sin^-1(x/y) + cos(y/x)

In summary, the conversation discusses the partial derivative of U with respect to y for inverse sin and the use of the chain rule in determining the derivative. The final answer is -y/x and it is suggested to search for a list of derivatives using a computer. The person asking the question is advised to show their attempt or explain their doubt for a better understanding of the problem.
  • #1
ksurabhi
3
0
if U = sin^-1 (x/y) +cos(y/x) then Ux/Uy = ?


ans is -y/x.


i have specially doubt on the partial derivative of U w.r.t y for inverse sin.


thank you in advance
 
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  • #2
U/U=1. Ux/Uy = x/y. There is a separate homework forum. We do not do homework here.
The derivative is the sum of the partial derivatives. Any partial derivative is determined by considering all other variables as constant. dSin(x/y) would be = ∂(sin(cx))dx + ∂(sin(k/y))dy where I used c and k to emphasize that the other variable is considered constant during the differentiation of that term.
 
  • #3
i have specially doubt on the partial derivative of U w.r.t y for inverse sin.
... if only there was some special way you could search for a list of derivatives with your computer.

Please show your best attempt - or try to tell us about your doubt.
Otherwise we cannot know what your problem is.
 

1. What is a partial derivative?

A partial derivative is a mathematical concept used in multivariable calculus to calculate the rate of change of a function with respect to one of its variables while holding all other variables constant.

2. How do you find the partial derivative of a function?

To find the partial derivative of a function, you take the derivative with respect to the variable in question while treating all other variables as constants. In the case of the function U = sin^-1(x/y) + cos(y/x), we would take the partial derivative with respect to x and y separately.

3. What is the partial derivative of U = sin^-1(x/y)?

The partial derivative of U = sin^-1(x/y) with respect to x is 1/√(1-(x/y)^2). This can be found by using the chain rule and the derivative of the inverse sine function.

4. What is the partial derivative of U = cos(y/x)?

The partial derivative of U = cos(y/x) with respect to y is -1/x*sin(y/x). This can be found by using the chain rule and the derivative of the cosine function.

5. What is the partial derivative of U = sin^-1(x/y) + cos(y/x)?

The partial derivative of U = sin^-1(x/y) + cos(y/x) is 1/√(1-(x/y)^2) - 1/x*sin(y/x). This can be found by taking the partial derivatives of each term and adding them together.

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