- #1

fiziksfun

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## Homework Statement

We have

y' = y^(1/3)

with initial condition y(0)=0

It's stated that the partial derivative ∂f/∂y does not exist at y=0.

Can anyone explain to me why this is?

I don't understand how you can take the partial derivative if its not in the form f(x, y);

there is no x.

## Homework Equations

Solving for y we have

y = ((2/3)[t+c])^(3/2)

if c=o, the initial condition is satisfied

## The Attempt at a Solution

help!