1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Partial derivatives

  1. Sep 30, 2005 #1
    If sin (2x+4y+z) = 0 , find the first partial derivatives [tex]\frac{dz}{dx}[/tex] at the point (0,0,0)

    A.) [tex]\frac{dz}{dx}(0,0,0) =[/tex] _________________

    isnt this saying get the derivative of z, respect to x? i'm just kinda confuse since the variable 'z' is also in the problem.


    well i got the derivative of that function with respect to x and got 2*cos(2x+4y+z), plugged in 0,0,0 and got 2*cos(0), which is wrong. the answer should be -2*cos(0), where did the negative sign come from?
     
  2. jcsd
  3. Oct 1, 2005 #2

    Galileo

    User Avatar
    Science Advisor
    Homework Helper

    Judging from the question, You should regard z as a function of x (and possibly y).
    So you are given that:

    [tex]\sin(2x+4y+z(x,y))=0[/tex]

    Now use partial differentiation to find dz/dx.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Partial derivatives
  1. Partial Derivatives (Replies: 5)

  2. Partial Derivatives (Replies: 5)

  3. Partial Derivative (Replies: 7)

  4. Partial derivatives (Replies: 16)

  5. Partial Derivation (Replies: 7)

Loading...