form the differential equation for the follwing equation (x^2)/a^2 +(y^2)/b^2+(Z^2)/c^2 =1
Apr 19, 2005 #1 dvs77 12 0 form the differential equation for the follwing equation (x^2)/a^2 +(y^2)/b^2+(Z^2)/c^2 =1
Related Differential Equations News on Phys.org Study links Asian carp with Mississippi River fish drop Research sheds light on the underlying mechanics of soft filaments A marvelous molecular machine
Related Differential Equations News on Phys.org Study links Asian carp with Mississippi River fish drop Research sheds light on the underlying mechanics of soft filaments A marvelous molecular machine
Apr 22, 2005 #3 cepheid Staff Emeritus Science Advisor Gold Member 5,183 35 I read that as: Form the differential equation for the following equation: [tex] \frac{x^2}{a^2} + \frac{y^2}{b^2} + \frac{z^2}{c^2} = 1 [/tex] I don't get it...how do you get a PDE out of that?
I read that as: Form the differential equation for the following equation: [tex] \frac{x^2}{a^2} + \frac{y^2}{b^2} + \frac{z^2}{c^2} = 1 [/tex] I don't get it...how do you get a PDE out of that?
Apr 22, 2005 #4 dextercioby Science Advisor Homework Helper Insights Author 12,960 536 No,find the PDE whose solution is the ellipsoid's implicit equation... Daniel.
Apr 22, 2005 #5 cepheid Staff Emeritus Science Advisor Gold Member 5,183 35 I see, ok. That wasn't really clear before.
May 2, 2005 #7 kleinwolf 293 0 Well for this last question : suppose you have a 1st order PDE, then just derive again and you get a 2nd order one... The question is a bit ambigous...let's take a simpler exemple, nonparametric : y(x)=x^2 Then there are an infinity of differential equation having that solution : y'=2Sqrt(y) y''=y'/Sqrt(y) aso.... Moreover I don't know if you want the parametric equation or the explicit version...(ie. x=x(theta,phi) or x=x(y,z)...) Just plug in this in your equation and differentiate....
Well for this last question : suppose you have a 1st order PDE, then just derive again and you get a 2nd order one... The question is a bit ambigous...let's take a simpler exemple, nonparametric : y(x)=x^2 Then there are an infinity of differential equation having that solution : y'=2Sqrt(y) y''=y'/Sqrt(y) aso.... Moreover I don't know if you want the parametric equation or the explicit version...(ie. x=x(theta,phi) or x=x(y,z)...) Just plug in this in your equation and differentiate....