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Partial Differential Equations
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[QUOTE="Tsunoyukami, post: 4539729, member: 274774"] Ahh, that method seems a lot cleaner and nicer than what I was going for... I'm sure it's possible for me to get the same result by using the method I began to employ in my initial post if I were able to express ##dx'## in terms or some combination of ##dx## and ##dy##. I doubt it's as simple as just ##dx' = a dx + b dy## (because I still wouldn't be able to work my way from there to the final result). I'm just curious to see how I could plow forward with the coordinate method because I expect its possible as the two methods should be equivalent. [/QUOTE]
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