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## Main Question or Discussion Point

Iv forgotten the basics of this. How do we go about differentiating 3x^2 y^2 w.r.t y? I know the answer is 3x^2 y^2 but could someone explain this for me please?

- Thread starter cabellos
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Iv forgotten the basics of this. How do we go about differentiating 3x^2 y^2 w.r.t y? I know the answer is 3x^2 y^2 but could someone explain this for me please?

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cristo

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You want to perform [tex]\frac{\partial}{\partial y}(3x^2y^2)[/tex].Iv forgotten the basics of this. How do we go about differentiating 3x^2 y^2 w.r.t y? I know the answer is 3x^2 y^2 but could someone explain this for me please?

You would simply treat the function of x as a constant and differentiate y normally, thus yielding [itex]6x^2y[/itex].

However, this is not what your answer is, so I wonder whether it is the correct question?

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cristo

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Erm.. no it wouldn't.

Unless you mean z=x

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i need some sleep!! Yeah i meant y^3 lol !

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Gib Z

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