As part of finding the integral of z/(z^2 -1), I'm stuck on getting the partial fraction for it. 1/2 [(1/(z-1) - 1/(z+1)] gives 1/(z^2-1). What should I do to get the z in the numerator. Any hints welcome.(adsbygoogle = window.adsbygoogle || []).push({});

Regards

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# Partial fraction of integrand

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