- #1

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## Homework Statement

∫(5x

^{2}+20x+6)/(x

^{3}+2x

^{2}+x

## Homework Equations

## The Attempt at a Solution

(5x

^{2}+20x+6)/(x

^{3}+(x(x

^{2}+2x+1)

(5x

^{2}+20x+6)=(A/x)+(B/(x+1))+(C/(x+1))

(5x

^{2}+20x+6)=x

^{2}(A+B+C)+x(2A+B+C)+A

5=A+B+C

20=2A+B+C

6=A

It's not coming out quite right. Did I maybe factor the denominator incorrectly?