- #1

KLscilevothma

- 322

- 0

^{2})/(1+u

^{4}) in partial fraction before I can proceed.

1+u

^{4}= (u

^{2}-2u+2)(x

^{2}+2u+2)

therefore 1+u

^{2}= (Au+B)(x

^{2}+2u+2) + (Cu+D)(u

^{2}-2u+2)

and I need to find out A, B, C and D

But wait, the next step in my textbook contains something like (1+sqrt(2)u+u

^{2}) and (1-sqrt(2)+u

^{2}) in denominators, so what is the problem and where does sqrt(2) come from ?

PS

original question:

[inte]dx/[(1+x

^{2})(sqrt(1-x

^{2}))]

and the substitution used is :

u=sqrt[(1-x)/(1+x)]