Partial fractions help!

  • #1
The integral of [(x+2/(x+4)]^2

A/(x^2+4) + B/[(x^2+4)^2)

A=0, B=1

so, the integral of 1/(x^2+4)^2

how do you do this?
 

Answers and Replies

  • #2
612
1
Let u = 2tan and don't use partial fractions…
 
  • #3
JonF said:
Let u = 2tan and don't use partial fractions…
I think even when you don't do as what you said in your post, surely you can still find out A LOT OF SOURCES to get this THING solved. Why never look for books around you ? I am sure you should have a lot, because maths computation is what you like, which your presence here already tells me, RIGHT ?

Just a suggestion anyway, since not everyone has an American dream.. For example, me, call me Alexsan, a psychologist-to-be, mainly plays around with alcohols and chemical reactions.
 
  • #4
NINHARDCOREFAN said:
The integral of [(x+2/(x+4)]^2

A/(x^2+4) + B/[(x^2+4)^2)

A=0, B=1

so, the integral of 1/(x^2+4)^2

how do you do this?
Hehe, Now your turn!

1~ Is it true that you don't understand how to solve the problem or you want to play around with your misinformation?
2~ You first correct your mistake made in your OP, then I will try to help you_UP.

AlexContourPlus
 

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