- #1

- 116

- 0

A/(x^2+4) + B/[(x^2+4)^2)

A=0, B=1

so, the integral of 1/(x^2+4)^2

how do you do this?

- Thread starter NINHARDCOREFAN
- Start date

- #1

- 116

- 0

A/(x^2+4) + B/[(x^2+4)^2)

A=0, B=1

so, the integral of 1/(x^2+4)^2

how do you do this?

- #2

- 612

- 1

Let u = 2tan and don't use partial fractions…

- #3

- 6

- 0

I think even when you don't do as what you said in your post, surely you can still find out A LOT OF SOURCES to get this THING solved. Why never look for books around you ? I am sure you should have a lot, because maths computation is what you like, which your presence here already tells me, RIGHT ?JonF said:Let u = 2tan and don't use partial fractions…

Just a suggestion anyway, since not everyone has an American dream.. For example, me, call me Alexsan, a psychologist-to-be, mainly plays around with alcohols and chemical reactions.

- #4

- 6

- 0

Hehe, Now your turn!NINHARDCOREFAN said:

A/(x^2+4) + B/[(x^2+4)^2)

A=0, B=1

so, the integral of 1/(x^2+4)^2

how do you do this?

1~ Is it true that you don't understand how to solve the problem or you want to play around with your misinformation?

2~ You first correct your mistake made in your OP, then I will try to help you_UP.

AlexContourPlus

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