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Find the inverse Laplace transform of

[tex]\frac{s-2}{s^3+2s^2+2s}[/tex]

I think once I get the expression simplified I can do the rest by myself. I started to separate this expression out by partial fractions and got as far as this:

[tex]\frac{s-2}{s^3+2s^2+2s}=\frac{s-2}{(s^2+2s+2)s}=\frac{As+B}{s^2+2s+2} +\frac{C}{s}[/tex]

[tex](As+B)s+C(s^2+2s+2)=s-2[/tex]

From this expression I got C=-1, which I checked was correct by using my calculator, but I still don't know how to find A, or B. Can anyone help with this please?

Any ideas or hints on how to do the inverse would be also be appreciated.

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# Homework Help: Partial-fractions problem

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