I have: [tex] \frac{(1+j\omega)(3-j\omega)}{(3+j\omega)(3-j\omega)} [/tex](adsbygoogle = window.adsbygoogle || []).push({});

When I perform the partial fraction expansion I get:

[tex] \frac{-2}{3+j\omega} [/tex]

Where my calculator gets:

[tex] 1 - \frac{-2}{3+j\omega} [/tex].

Why am I wrong?

I am performing the expansion as follows:

[tex] \bar F(s) = \frac{(1+s)(3-s)}{(3+s)(3-s)} [/tex]

and,

[tex] K_i = (s+p_i)\bar F (s) [/tex] where: [itex] s = - p_i [/tex]

note: [tex] p_i [/tex] corresponds to 3 and -3 respectively. I am getting:

[tex] K_1 = -2 [/tex]

and [tex] K_2 = 0 [/tex]

(this does not match my calculator.

I am assuming simple poles. Is this not proper?

thanks in advance!

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# Homework Help: Partial Fractions

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