- #1
- 1,169
- 5
For a rational function, (x^2+1)/(x^2-1) = (x^2+1)/[(x+1)(x-1)], if we were to split it into partial fractions so that (x^2+1)/(x^2-1) = A/(x+1) + B/(x-1) = [A(x-1) + B(x+1)]/(x^2-1)...solving for A and B get us A = -1 and B = 1. This would mean that (x^2+1)/(x^2-1) = 2/(x^2-1)...which doesn't seem right; x^2+1 is 2 greater than x^2-1, so (x^2+1)/(x^2-1) can be rewritten as 1 + 2/(x^2-1), which is 1 greater than the function I got earlier. Why is there a discrepancy?