[tex]\frac{s-1}{s(s-2)^2}[/tex](adsbygoogle = window.adsbygoogle || []).push({});

How can I expand this fraction?

[tex]\frac{A}{s} + \frac{B}{(s-2)} + \frac{C}{(s-2)^2}[/tex]

right?

This gives me the equation

[tex]As^3 - 6As^2 + 12As - 8A Bs^3 - 4Bs^2 + 4Bs + Cs^2 - 2Cs = s-1[/tex]

so that

(1) A + B =0

(2)- 6A - 4B + C = 0

(3) 12A + 4B - 2C = 1

(4) -8A = -1

(4) gives A = 1/8

(1) gives B = -1/8

(2) gives C = 1/4

The correct answer is

A = -1/4

B = 1/4

C = 2/4

What's wrong?

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# Homework Help: Partial fractions

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