i will use "\int" as a integral sign since latex is down.(adsbygoogle = window.adsbygoogle || []).push({});

\int (7)/(x^2-1)*dx

using partial fractions...

took out the 7...

7\int (1)/(x+1)(x-1)

A(x-1) + B(x+1) = 7

if x = 1, B=7/2

if x = -1, A= -7/2

ok it's time to set up my integral function:

7\int -7/2(x-1) + 7\int 7/2(x-1)

take out the 7...

14\int -1/2x-1 + 14\int 1/2x-2

now to solve the integrals

14(-ln(2x-2) + ln(2x-2)) + c

where did i go wrong?

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# Homework Help: Partial fractions

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