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Partial Pressure Calculation

  1. Jul 8, 2013 #1
    1. The problem statement, all variables and given/known data

    I am given the following equation:

    2NO (g) + Cl2 (g) [itex]\rightleftharpoons[/itex] 2NOCl (g)

    Kp = 6.5×104
    PNO = 0.35 atm
    PCl2 = 0.10 atm

    I need to calculate PNOCl.

    2. Relevant equations

    Kp = [itex]\frac{(P_{NOCl})^2}{(P_{NO})^2*(P_{Cl_2})}[/itex]

    3. The attempt at a solution

    I was given Kp = 6.5×104

    After plugging in my partial pressures for NO and Cl2 I got:

    PNOCl = [itex]\sqrt{(6.5×10^4)*(0.35)^2*(0.10)}[/itex]

    Is this the correct way to calculate this?

    Thanks!!
     
    Last edited: Jul 8, 2013
  2. jcsd
  3. Jul 9, 2013 #2
    That looks good to me!
     
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