- #1
elliotyang
- 5
- 0
The gas phase decomposition of ethylamine produces ethane and ammonia according to the following equation:-
C2H5NH2 (g) → C2H4 (g) + NH3 (g)
The following total pressures were found for this reaction at 500°C with an initial pressure of pure ethylamine equal to 55 mm Hg.
Ptotal (mm Hg) time (min)
55 0
64 2
72 4
89 10
93 12
If P0 is the initial pressure of reactant and ptotal is the total pressure at time t, show how the the partial pressure of reactant remaining at time t can be found.
Can anyone give hint to me how to start to solve this question?
is it i have to apply avogadro's law?
C2H5NH2 (g) → C2H4 (g) + NH3 (g)
The following total pressures were found for this reaction at 500°C with an initial pressure of pure ethylamine equal to 55 mm Hg.
Ptotal (mm Hg) time (min)
55 0
64 2
72 4
89 10
93 12
If P0 is the initial pressure of reactant and ptotal is the total pressure at time t, show how the the partial pressure of reactant remaining at time t can be found.
Can anyone give hint to me how to start to solve this question?
is it i have to apply avogadro's law?