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Partial Pressures

  1. Nov 24, 2011 #1
    a) Determine K at 298K for the reaction H2(g) + Cl2(g) <---> 2HCl(g)
    b) The equilibrium partial pressure of HCl is 1 bar. Determine the equilibrium partial pressures of H2 and Cl2.


    This question was on my test. I got K= 3.2 x 10^-34 using dG*=-RTlnK when dG=0 at equilibrium. I'm having trouble determining the partial pressures. I know that Pj=(xj)(Ptot). I also know that K= (PHCl)^2/(PH2)(PCl2), but I still don't know how to determine the partial pressure just based off of PHCl=1 bar???
     
  2. jcsd
  3. Nov 24, 2011 #2

    Borek

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    Staff: Mentor

    You are most likely to assume you started with HCl and all H2 and Cl2 are products of dissociation. This, plus stoichiometry, gives you all information you need to solve the problem.
     
  4. Nov 24, 2011 #3
    I figured it out. thanks
     
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