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Particle Collision

  • Thread starter Air
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  • #1
Air
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Homework Statement


The results of particle collisions are observed using particle detectors. Sometimes the products of these collisions are themselves unstable and decay to give further particles; the products of decay can be photons.

In one collision, a stationary [itex]\pi^\circ[/itex] meson is produced which then decays to give two gamma ray photons. The rest mass of the meson is [itex]135 \ MeV/c^2[/itex].

[itex]\pi ^\circ \rightarrow \beta + \beta[/itex]​

Calculate the wavelength of each photon.


Homework Equations


[itex]E = hf = \frac{hc}{\lambda}[/itex]


The Attempt at a Solution


How can I find [itex]E[/itex]? I can carry on from that point but I don't know which equation to use to find [itex]E[/itex]?
 
Last edited:

Answers and Replies

  • #2
240
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The energy of the stationary meson is calculated using E = mc2

Epi = mpi*c2 = 135 MeV / c2 * c2 = 135 MeV
 
Last edited:

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