Suppose a particle is confined in one dimension to a region of width L. Obtain an approximate formula for its minimum kinetic energy.
ΔxΔp ≥ h/4π
The Attempt at a Solution
1. Put L in for Δx
2. Divide by L. It is positive
3. Δp ≥ h/(4πL)
4. KE = (p^2)/2m
Now what? Ok, so you're telling me that the uncertainty in the momentum can be determined. What does that say about the actual value of the momentum? Wouldn't the minimum momentum technically be zero? Wouldn't this mean the minimum KE is zero? There is no way this is right... It would be too easy..
Please please please help with this. My teacher is so bad and this of all classes is the class I'm falling behind in.. It's his first semester teaching and he just runs through calculations all day and apparently expects us to learn all this stuff at home.. I don't have time for this. A simple explanation will do me wonders. Thanks so much