1. The problem statement, all variables and given/known data 1) A particle inside a one dimensional box with impenetratable walls at x=-a and x=+a has an energy eigenvalue of 2 eV. What is the lowest energy that the particle can have? 2. Relevant equations E(n) = (n^2)E(o) where E(o)=h^2/(8mL^2) 3. The attempt at a solution I started in the following way: If E(o) is the zero point energy. Then, 2 eV = (n^2)E(o) Where does it lead to?