1) A particle inside a one dimensional box with impenetratable walls at x=-a and x=+a has an energy eigenvalue of 2 eV. What is the lowest energy that the particle can have?
E(n) = (n^2)E(o)
The Attempt at a Solution
I started in the following way:
If E(o) is the zero point energy. Then,
2 eV = (n^2)E(o)
Where does it lead to?