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## Homework Statement

1) A particle inside a one dimensional box with impenetratable walls at x=-a and x=+a has an energy eigenvalue of 2 eV. What is the lowest energy that the particle can have?

## Homework Equations

E(n) = (n^2)E(o)

where E(o)=h^2/(8mL^2)

## The Attempt at a Solution

I started in the following way:

If E(o) is the zero point energy. Then,

2 eV = (n^2)E(o)

Where does it lead to?