# Particle in A Box

1Fizziks8r
Is the ground state wavefunction of a particle in a 3-D cubic box with V=0 an eigenstate of the z-direction orbital angular momentum operator, Lz?

I tried to determine this using cartesian coordinates, but I ended up with an imaginary answer for Lz(Psi), which is supposed to be a Hermitian operator.

Intuitively, I want to say that the ground state IS an eigenstate with an eigenvalue=0, but I can't get that to come out computationally.

Any help?