- #1

- 208

- 14

- Homework Statement
- A particle is confined in a one dimensional potential box with impenetrable walls at x = ±a. Its energy eigenvalue is 2eV and corresponds to the eigenfunction of the first excited state. What is the lowest possible energy of the particle ?

- Relevant Equations
- Hψ = Eψ

E = (nπ hbar)^2/2mL^2

For calculating minimum E, I have n = 1, L = 2a & ψ = 2.

But I am not getting how to exactly find its value.

Please help me !

But I am not getting how to exactly find its value.

Please help me !