# Particle in hemispherical bowl

[SOLVED] Particle in hemispherical bowl

## Homework Statement

A 195 g particle is released from rest at point A along the horizontal diameter on the inside of a frictionless, hemispherical bowl of radius R = 31.0 cm.
http://www.webassign.net/pse/p8-52.gif

(a) Calculate the gravitational potential energy of the particle-Earth system when the particle is at point A relative to point B.
(b) Calculate the kinetic energy of the particle at point B.
(c) Calculate its speed at point B.
(d) Calculate its kinetic energy when the particle is at point C.
(e) Calculate the potential energy when the particle is at point C.

## The Attempt at a Solution

(a)PE=mgh so PE=.195kg*9.8m/s^2*.31m=.59241J

(b)KE=.5mv^2 but I have no idea how to find the velocity at the point. Any help?

(d)Also need to know how to calculate velocity at this point...

(e)PE=mgh=(.195kg)(9.8m/s^2)(.2067m)=.39494

Any help on b, c, and d?

tiny-tim
Homework Helper
Hi sailsinthesun!

(a) and (e) seem ok.
(b)KE=.5mv^2 but I have no idea how to find the velocity at the point. Any help?

KE=.5mv^2 is the answer to (b)! That's all (b) asks you for!

For (c) and for (d), you use "conservation of energy": KE + PE = constant (which, btw, should be in your "Relevant equations"). (b)KE=.5mv^2 but I have no idea how to find the velocity at the point. Any help?