A particle moving along the x-axis has its velocity described by the function vx = 5t^2 m/s, where t is in s. Its initial position is x0 = 1 m at t0 = 0 s. At t = 1 s, find the position, velocity, and acceleration of the particle.
So from that equation... vx = 5t^2, x0 = 1m, t0 = 0s, t1 = 1s
v1 = v0 + at
x1 = x0 + v0 + (1/2)at^2
The Attempt at a Solution
So for the velocity, I just plugged in 1s for t and got 5.0m/s, which is correct. I'm stuck on the acceleration and position though, and I'm thinking it's because I don't know what v0 is. I assumed v0 = 0 because don't you plug in 0 for t in the given function? Which then the answer is 0. Any thoughts?