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Particle on an inclined plane.

  1. Feb 28, 2016 #1
    1. The problem statement, all variables and given/known data
    When resolving forces on an inclined plane, can anyone explain to me why 1.2g in my pic is used as the hypotenuse? It looks intuitively like it should be the opposite or adjacent.

    Thanks for any help :)

    IMG_20160228_141712072.jpg

    2. Relevant equations


    3. The attempt at a solution
     
  2. jcsd
  3. Feb 28, 2016 #2

    Doc Al

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    Staff: Mentor

    Whenever you resolve a vector into components that vector will be the hypotenuse. (Don't confuse the triangle of the inclined plane with the triangle you need when resolving a vector.)
     
  4. Feb 28, 2016 #3

    Doc Al

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    Staff: Mentor

    Read this: Inclined Planes
     
  5. Feb 28, 2016 #4
    Thank you
     
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