- #26

BruceW

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This is correct! :)For radial direction,

[itex]F_r=ma_r \Rightarrow r\omega^2=\ddot{r}[/itex]. The solution of this differential is asked in the question.

For azimuthal direction,

[itex]F_{\theta}=ma_{\theta} \Rightarrow N=2m\dot{r}\omega[/itex]. I am sorry if this wrong. Please have a look at my attempt on the other part of the given question.