1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Partition law

  1. Apr 26, 2010 #1
    1. The problem statement, all variables and given/known data

    When 200 cm^3 of an aqueous solution X with concentration 10.0 g/dm^3 was shaken with 100cm^3 of solvent 1-pentanol , 1.60 g of X was extracted . If the aqueous solution was once again shaken with 100 cm^3 of 1-pentanol after the first extraction , what is the mass of X extracted ? [The molecular state of X in water and in 1-pentanol are the same]

    2. Relevant equations



    3. The attempt at a solution

    1000 cm^3 of aqeous solution gives 10 g of X so 200 cm^3 of aqueous solution gives 2 g of X .

    the partition constant , K = (1.6/100)/(0.4/200) , K=8

    Second extraction ,

    8=(X/100)/((0.4-X)/200)

    so X=0.32 g

    Am i correct ?
     
  2. jcsd
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Can you offer guidance or do you also need help?



Similar Discussions: Partition law
  1. Stuck with Hess's Law (Replies: 0)

  2. Beer's law (Replies: 0)

  3. Rate laws (Replies: 0)

  4. Rate Law problem (Replies: 0)

Loading...