# Homework Help: Partition law

1. Apr 26, 2010

### thereddevils

1. The problem statement, all variables and given/known data

When 200 cm^3 of an aqueous solution X with concentration 10.0 g/dm^3 was shaken with 100cm^3 of solvent 1-pentanol , 1.60 g of X was extracted . If the aqueous solution was once again shaken with 100 cm^3 of 1-pentanol after the first extraction , what is the mass of X extracted ? [The molecular state of X in water and in 1-pentanol are the same]

2. Relevant equations

3. The attempt at a solution

1000 cm^3 of aqeous solution gives 10 g of X so 200 cm^3 of aqueous solution gives 2 g of X .

the partition constant , K = (1.6/100)/(0.4/200) , K=8

Second extraction ,

8=(X/100)/((0.4-X)/200)

so X=0.32 g

Am i correct ?