(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

When 200 cm^3 of an aqueous solution X with concentration 10.0 g/dm^3 was shaken with 100cm^3 of solvent 1-pentanol , 1.60 g of X was extracted . If the aqueous solution was once again shaken with 100 cm^3 of 1-pentanol after the first extraction , what is the mass of X extracted ? [The molecular state of X in water and in 1-pentanol are the same]

2. Relevant equations

3. The attempt at a solution

1000 cm^3 of aqeous solution gives 10 g of X so 200 cm^3 of aqueous solution gives 2 g of X .

the partition constant , K = (1.6/100)/(0.4/200) , K=8

Second extraction ,

8=(X/100)/((0.4-X)/200)

so X=0.32 g

Am i correct ?

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Partition law

Can you offer guidance or do you also need help?

Draft saved
Draft deleted

**Physics Forums | Science Articles, Homework Help, Discussion**