# Path of particle in field

## Homework Statement

The temperature is given by

$$T(x,y)=\sqrt{2}e^{-y}\cos x$$

Calculate the path of a heat-seeking particle.

## The Attempt at a Solution

$$\nabla f(x,y)=\left[\begin{array}{c} -\sqrt{2}e^{-y}\sin x\\ -\sqrt{2}e^{-y}\cos x\end{array}\right]$$

$$g(t)=\left[\begin{array}{c} g_{1}(t)\\ g_{2}(t)\end{array}\right]$$

$$\dot{g}_{1}(t)=-\sqrt{2}e^{-g_{2}(t)}\sin g_{1}(t)$$
$$\dot{g}_{2}(t)=-\sqrt{2}e^{-g_{2}(t)}\cos g_{1}(t)$$

That's where I'm stuck. I have to solve the differential equations but they depend very heavily on each other so I can't get them decoupled.
Also tried to solve them in maple but maple just complains that the numverator of the ODE depens on the highest derivative.

Do I missing something obvious? (we did differential equations only briefly)

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olgranpappy
Homework Helper
what's "f"?

HallsofIvy
$$\frac{dy}{dx}= \frac{-\sqrt{2}e^{-y}sin(x)}{-\sqrt{2}e^{-y}cos(x)}$$